plus ten times a negative five is a negative fifty.

negative two times a negative two is a plus four

negative three is a negative three

so add the negative fifty and the plus four and the negative three 50 + 4 – 3 and get 51

a negative of a negative is positive

for example: 2–1 is the same as 2+1

a negative times a negative is a positive

for example: -2(-3) = 6

a negative times a positive is a negative

so the problem

-5(-2)(-2–3)- -2(-2)+(-3)

start with the parentheses

-5(-2)(-2+3)- -2(-2)+(-3)

then -5(-2)(1)- -2(-2)+(-3)

then multiply

-5(-2)(1)=10

so

10- -2(-2)+(-3)

and -2(-2)=4

so

10-4+(-3)

10-4=6

6+(-3) is the same as 6-3

which is 3

the second problem:

break the figure up into a semi circle and a rectangle

the equation for a semi circle is 1/2 pi r^2

the radius is 25 ft so

1/2 pi 25^2= 625pi/2 or about 981

the bottom half of the figure is a rectangle which you probably know is height X width

then you add the two together

Hope this helps

Use the order of operations (PEMDAS) to solve and get this answer. Start by doing things in the ()’s, then the exponents, then multipulcation, then division, addition, and finally subtraction.

The easiest way to calculate the area of the figure is to divide it into parts. We will start with the half circle.

The area of a complete circle is (pi) * (radius of circle)^2. Because we are only dealing with a half a circle, we

will divide that whole thing by two. So you have [(pi)(r)^2]/2. If you are in a basic math class, you are

probably using 3.14 for the value of pi, and you said that the radius is 4, so you have [(3.14)(4)^2]/2.

This is equal to [3.14*16]/2, which equals 50.24/2 = 25.12.

The other part of the diagram is a rectangle. To find the area of this part multiply the base (the bottom, in this case) by the height (the side in this case). You only gave one measurement, so I cannot give you the area of the rectangle; I would need to know the length of both the bottom and the side.

The total area is the sum of these two parts : the area of the half circle (25.12) plus the area of the rectangle.

-5(-2)(-2–3)–2(-2)+(-3)

-5(-2)(-2+3)+2(-2)-3

then you use the order of operations to continue solving;

-5(-2)(-2+3)+2(-2)-3

10(1)+2(-2)-3

10-4-3

=3

so the answer is 3

for the second problem:

you solve 2 different problems. first you need to solve for the half cirlce and hten the rectangle and then you add the 2 areas together to get the total area.

1/2 circle = (1/2)pi*r^2

=(1/2)(3.14)(4^2)

=(.5)(3.14)(16)

=25.12 yds^2

if i’m understanding the rectangle part, it is 5 yds by 50 yds? if that’s the case, then it is

rectangle=l*w

=5*50

=250 yds^2

then you add 250+25.12 and that equals 275.12 yds^2, which is yoru total area!

email me at [email protected] if you have any other questions!

area of semicircle = 1/2 times pi times radius squared = .5 times 3.14 times 25 times 25

then add the answers

So when you look at the problem- you can see there are two sums- focus on the brackets first then work on the outside brackets next.

so it rlly isnt a big deal that ur 13.

btw i noe the answer but srry, i think that its wrong to tell u

cus then it wouldnt be ur own work,

therfore cheating

srry