A few days ago
Inverse functions?
I’m looking at an example problem and I’m confused. The question is: Which of the functions is the inverse function of f(x)=5/x-2?
The answer is h(x)=5/x+2 but I keep getting x/5+2.
f(x)=5/x-2
y=5/x-2
x=5/y-2
x/5=y-2
x/5+2=y
What process am I doing incorrectly?
Top 2 Answers
A few days ago
Favorite Answer
Step 3 to step 4:
x = 5/(y – 2)
y – 2 = 5/x, not x/5
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A few days ago
To find the inverse you need to
1. write the equation with y, f(x) =y
y=5 / x-2
2. Interchange x and y
x =5 /y-2
3. Then make y the subject again
cross-multiply
x(y-2)=5
xy-2x=5
xy=5+2x
y=5+2x /x
which is
y=5/x +2x/x
y=5/x + 2
The problem is in your fourth line. You cannot move the 5 the way you are. Check the answer again.
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