regardin fraction mentioned in the add details?

In a fraction, if 1 is added to both the numerator at the denominator, the fraction becomes 1/2. If numerator is subtracted from the denominator, the fraction becomes 3/4. Find the fraction.

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A few days ago

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Let the numerator = x and denominator = y

Therefore:

(x+1)/(y+1) = 1/2 and x/((y-x) = 3/4

simplifying the first equation,

(x+1) = 1/2(y+1)

2(x+1) = (y+1)

2x + 2 = y + 1

so y = 2x + 1

substitute this into the second equation

x/(y-x) = 3/4 where y = 2x+1

x / (2x+1 – x) = 3/4

x / (x+1) = 3/4

x = 3/4(x+1)

4x = 3x + 3

x = 3

use x=3 to find y using y = 2x+1

and thus: y = 2(3) + 1 = 7

The fraction is 3/7 (check it by testing (3+1)/(7+1) = 4/8 = 1/2 and 3/(7-3) = 3/4

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regardin fraction mentioned in the add details?

regardin fraction mentioned in the add details?

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