(9x^2y^6)(x^6y^6)

9x^8y^12 <=ANSWER 2. (-5c^2d^4)^2(c^4d^7)^4 (25c^4d^8) (c^16d^28) (25c^20d^36) <=ANSWER 3. 4^3/4^1 64/4 16 <=ANSWER 4. t^8/t^2 t^6 (cancel exponents: 8/6 )

5. x^2/x^5

x^-3 (negative exponent means we have to “turn” the digit, int his case it’ll be a fraction)

1/x^3 (1 over x^3 )

GOOD LUCK!!!

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The first half would look like this:

[9(x^2)(y^6)]

The second one would look like this:

[(x^6)(y^6]

Most problems like that in Algebra would now expect you to multiply those any farther, so your answer would be:

[9(x^2)(y^6)] x [(x^6)(y^6)]

#2 you do the same thing.

#3 Would be fairly simple.

Raise 4^3 and you get 4x4x4 = 64.

Then raise 4^1 and you get 4.

So basically divide 64 by 4.

64/4 = 16

#4is simple also. Divide t^8 by t^2, when you divide exponents you use subtraction. So the exponents are 8 and 2, simply subtract.

8-2=6

So the powers you have left over would be the exponent of t.

t^6