A few days ago
Likhitha

I don’t know how to do this problem…explain the steps plz?

A mechanic and his assistant took 2 1/4 hrs to assemble an engine. If his assistant works alone, he takes 6 hrs. How long will the mechanic take to assemble the engine if he works alone?

Top 1 Answers
A few days ago
blueskies

Favorite Answer

You have to think of the problem in terms of how much each person does “in a given unit of time”

Soo… if the mechanic and his assistant can assemble an engine in 2 1/4 hrs, and the assistant can assemble the engine by himself in six hours, then (this here is the trick!) together the mechanic and his assistant can do 1/(2 1/4) of the job per hour, and the assistant alone can do 1/6 per hour. How much then can the mechanic do per hour if he works alone?

To find out how much the mechanic can do alone per hour, subtract what the assistant can do by himself per hour from what both the mechanic and assistant can do together per hour: 1/(2 1/4) – 1/6 = 1/(2.25) – 1/6 = 1/(9/4) – 1/6 = 4/9 – 1/6 = 8/18 – 3/18 = 5/18. The mechanic can do 5/18 of the job per hour. Now let “t” stand for how long the mechanic takes to assemble the engine by himself. He can do 1/t per hour, so 5/18 = 1/t. Flip the equation, and you get that t = 18/5 = 3.6 hours. That is:

hours to completely assemble the engine:

together: 2 1/4 hrs

assistant: 6

mechanic: t

completed per hour:

together: 1/(2.25)

assistant: 1/6

mechanic: 1/t

subtracting their labor:

1/(2.25) – 1/6 = 1/t

5/18 = 1/t

18/5 = t

They can complete the job together in just over 3 1/2 hours.

HOPE THIS HELPS!!!!

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