Geometry Help?
write the equation of the parallel line of (2,3) with another point of (-2,-1).
heres a picture of what the line looks like:
http://priyabaenen.zoomshare.com/files/equation_slope_parallel_lines_example.bmp
the steps i figured out was:
1- find slope
2- plug i known numbers (the slope will be the same since the lines are parallel)
3- find (x,y) of parallel line.
4-then find b using algebra
i just dont know how to do it.
here are the equations to use:
slope= y2-y1/x2-x1
and the slope-intercept formula- y=mx+b
where m= slope and b=y-intercept.
please someone explain this to me!!
Favorite Answer
this is what i got.
y-3=2(x-2)
i found the slope between the points.
then plugged them into the point slope form (y-y1)=m(x-x1)
now, simplify it to get it into slope-intercept form: y=2x-1
(hint: i distributed and did addition property or equality and subtraction prop.)
now, you know the slope and y-intercept.
slope:2
y intercept: -1
i am not sure if thats what you mean, but thats what i got.
hope it helps.
good luck on your test.
:]
y = k*x + b
k = (y1 – y2) / (x1 – x2) = (3 + 1) / (2 + 2) = 4 / 4 = 1
So the equation is y = x + b.
b is an arbitrary parameter, that takes values from -inf to +inf, (there are infinitely many lines that are parallel to a give one).
You can determite the value of b ONLY if you have some additional constraints – for example, the point (1,2) belongs to the line.
m=3–1/2–2
m=4/4
m=1
we then plug in (2,3) (it could be the other point also) into the y=mx+b equation to find b
3=1(2)+b (substitute variables)
3=1+b (multiplying)
2=b (subtracting 1)
so your final equation is y=x+2
if you want to find a parallel line for this equation, you start off with y=x+b and pick a point (i’m just going to use (1,0))
0=1(1)+b (substitute to find b)
0=1+b (multiplying)
-1=b
so your parallel equation would be y=x-1
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