A few days ago

Anonymous

(6x+3)^2 + (6x+4)^2 = (8x+3)^2?

(6x+3)^2 + (6x+4)^2 =( 8x+3)^2

can someone explain in steps how to do this problem?

I cant understand it -_- please help me

i think there’s supposed to be 2 answers to this

the ^2 means the 2 is an exponent

Top 2 Answers

A few days ago

Favorite Answer

first you have to get rid of the exponents:

(36x²+36x+9)+(36x²+48x+16)=(64x²+48x+9)

because there is a 48x and a 9 on both sides, they cancel out:

(36x²+36x)+(36x²+16)=(64x²)

then you add and subtract like terms so that everything is on one side:

8x²+36x+16=0

then you factor out a four from each:

4(2x²+9x+4)=0

then you factor what is in the ()

A few days ago

Anonymous

(6x+3)^2 + (6x+4)^2 =( 8x+3)^2

1.36x^2+9+36x+36x^2+16+48x=64x^2+9+48x

2.36x^2+36x+36x^2+48x-64x^2-48x=-9-16+9

3.36x^2+36x+36x^2+48x-64x^2-48x=-16

4.8x^2+36x+16=0

5.Discriminant=36^2-4*8*16 Solve this, then step 6.

6.x1,x2(the 2 sollutions)=-36+-sqrt of Discriminant

7….

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