Word Problem help in Algebra I?
A bus traveling at an average rate of 30 mph left the city at 11:45 a.m. A car following the bus at 45 mph left the city at noon. At what time did the car catch up with the bus.
I don’t get how do solve it. or this on either.
Ellen and Kate raced on their bicycles to the library after school. They both left school at 3:00 p.m. and bicylced along the same path. Ellen rode at a speed of 12 pmh and Kate rode at 9 mph. Ellen got to the library 15 minutes before Kate.
a. How long did it take Ellen to get to the library?
b. At what time did Ellen get to the library?
Thank you for helping me understand this better, it will really help me on my test coming up Thursday!!:)
Favorite Answer
So:
30 * x = 45 * (x – 0.25)
Simplify both sides
30x = 45x – 11.25
Subtract 45x from both sides
-15x = – 11.25
Multiply both sides by -1
15x = 11.25
Divide by 15
x = 0.75
So the bus travelled .75 hours (or 45 minutes) when the car caught up. So the car caught up with the bus at 12:30pm.
For the second problem, we’ll have x (in hours) = Ellen’s time to get to the library. Therefore, we know the length of the trip was 12 * x. Kate travelled the same distance in (x + 0.25) hours.
So:
12 * x = 9 * (x + 0.25)
Simplify
12x = 9x + 2.25
Subtract 9x from both sides
3x = 2.25
Divide both sides by 3
x = 0.75
So it took Ellen 0.75 Hours or 45 minutes to get to the library. Which means she got there at 3:45pm, while Kate arrived at 4pm.
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