A few days ago
☆Sophie^^☆

um,,,,help,,,,,,,,?

Make the cubic y=ax^3+bx^2+cx+d pass through the points (0,6)(1,-2) and be tnagent to 3x-y=6 at (2,0)

Top 1 Answers
A few days ago
Anonymous

Favorite Answer

Substituting the coordinates of the points (0,6), (1,-2), and (2,0) into the cubic’s equation, we get:

d = 6

a + b + c + d = -2

8a + 4b + 2c + d = 0

The line

3x-y=6

<=> y = 3x – 6

has the slope of 3.

The slope of the cubic

y’ = 3ax² + 2bx + c

must be equal to 3 at x=2:

8a + 4b + c = 3.

Solving the system of equations:

d = 6

a + b + c + d = -2

8a + 4b + 2c + d = 0

8a + 4b + c = 3

we find that

a=2

b=-1

c=-9

d=6

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