A few days ago
The population of a city is 178500 and it grows at annual rate of 2.1%per annum?
The population of a city is 178500 and it grows at annual rate of 2.1%per annum, in how many years will the population grow to 210,000?
Top 6 Answers
A few days ago
Favorite Answer
210000/178500 = 1.17647, and so we need 1.021^n = 1.17647, and ln(1.17647)/ln(1.021) = n = 7.8, so about 8 years.
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A few days ago
It should take about 7 years, 9 months, 3 weeks, and 2 days.
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A few days ago
multiply the population (178,500) by 2.1% or (.021) and add the answer to your population (178,500)
so in about 7 years, 10 months the population will be 210,000
0
A few days ago
“Per annum” is latin for “per year”, or in this case, annually. Therefore, multiply 178,500 by 2.1% (or .021) and then add the result to 178500. This will yield the increase in the population.
Best of luck!
0
A few days ago
The equation to figure this out would be
178500+.021X=210000
First subtract 178500 from 210000
210000-178500=31500
so you get
.021X=31500
Then divide 31500 by .021
so X=1500000
1
A few days ago
9.2 years
0
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