this is actually quite easy…all you do is…

substitute whatever x is into the first equation….

so the first equation would read…

2y-1=3y+7 because the second equation tells us that x=2y-1

then you want to combine the like terms….

add 1 to both sides…

that leaves you with 2y=3y+8

then subtract 3y from both sides

that leaves you with -y=8

then divide by -1 so that x is positive

that leaves you with y= -8

then plug y=-8 into the first equation and solve for x…

x= -17…

so the solutions for x and y are -17 and -8

you can check your answer by plugging in the solutions you got

the solutions should work for both equations and they do

If there’s a quadratic, then there’ll maximum in all risk be 2 solutions. first of all, the addition approach could artwork completely in this technique. upload the terrific suited facets and the left facets to get. y + 5x + 6x^2 – 13x – y = 3 – 5 be conscious how the ‘y’s cancel out 6x^2 – 8x = -2 Divide the two facets by 2 3x^2 – 4x = -a million 3x^2 – 4x + a million = 0 (3x – a million)(x-a million) = 0 x = a million ; a million/3 Now plug it into the less complicated equation to sparkling up for y y + 5x = 3 y = 3 – 5x y = 3 – 5(a million) y = 3 – 5(a million/3) y = -2 ; 4/3 so the strategies are ( a million , -2 ) , ( a million/3 , 4/3)

x = -17, y = -8

i think you have your letters wrong