6(x+1) / (x-1) (x+1) + 5(x-1) / (x+1) (x-1) = 3x/x^2-1

6(x+1) / x^2 – 1 + 5(x-1) / x^2 – 1 = 3x/x^2 – 1

6(x+1) + 5(x-1) = 3x

6x + 6 + 5x -5 = 3x

8x = -1

x = -1/8

i think it’s right

6(x+1) +5(x-1) = 3x and you should be able to solve from there. Good luck

the least common denominator is x^2 – 1

multiply 6 / x-1 by (x+1)/x+1) and you get 6(x+1)/x^2 – 1

multiply 5/ x+1 by (x-1)/(x-1) and you get 5(x-1)/x^2 – 1

then add the fractions together:

6(x+1)/x^2 – 1 and 5(x-1)/x^2 – 1 equals to [5(x-1)+6(x+1)]/x^2 – 1

[5(x-1)+6(x+1)]/x^2 – 1 subtract 3x / x^2 – 1 so: [5(x-1)+6(x+1)-3x]/x^2 – 1 = 0

expand:

(5x-5+6x+6-3x)/x^2 – 1

(8x+1)/x^2 – 1