A few days ago
Anonymous

Multiplying Out Brackets (Expanding)…help?

Hi, well i have some math homework that i don’t get. It’s due tomorrow. and i don’t really get it. Here is the example.

Expand 5(2x+7) = 5 x 2x + 5 x 7 = 10x + 35

I don’t get it. Where does the + 5 come from? shouldn’t it be 5 x 2x + 7 ?

Here are the questions

1. 4 (x+3) *huh? x+3?*

2. 5 (x-6) *Again huh? x-6?*

3. 6 (2+4x) = 6 x 2 + 4x = 6 x 6x *Right?*

4. (-5) (2x-7) = -5 x -5x *How do you do that?*

5. 7p (2q-3) + 4q (3-3p) * I don’t get this at all. What’s p and q?*

Thanks in advance for your help. I feel like such an idiot i have to put my homework on Yahoo Answers…oh well, also please tell me how to do it, don’t just do them for me or else i won’t learn and i won’t know how to do the other ones. Thanks,

Tess

Top 2 Answers
A few days ago
MsMath

Favorite Answer

Let’s consider an example only with numbers.

5(2+7)

One way to do this would be to add the 2 and 7 first.

= 5(9)

Then multiply

= 45

Are you following so far?

Another way would be to use the distributive property.

5(2+7)

= 5(2) + 5(7)

= 10 + 35

= 45

Still following?

There is no extra 5. The five goes with the 2 and the 7.

If it was only suppose to go with the two, then it would be written this way

5(2) + 7

This gives you 10+7 = 17

See the difference? I hope this helps.

#1

4(x-3) = 4(x) + 4(-3) = 4x – 12

#2

5(x-6) = 5(x) + 5(-6) = 5x – 30

#3

6(2+4x) = 6(2) + 6(4x) = 12 + 24x

#4

-5(2x-7) = (-5)(2x) + (-5)(-7) = -10x + 35

#5

7p(2q-3) + 4q(3-3p)

= 7p(2q) + 7p(-3) + 4q(3) + 4q(-3p)

= 14pq – 21p + 12q – 12pq

Combine like terms (You can combine 14pq and -12pq).

= 2pq – 21p + 12q

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A few days ago
Feisling
5(2x+7)

you need to multiply 5 to 2x and you need to multiply 5 to 7. and thats when you get 10x+35.

exmaple if yu havethe equeation 5(2x+7+3y) then the solution would be 5 times 2x, 7 times 5 and 5 times 3y

10x+35+15y.

you need to distribute the multiplicand to the quantity in parethesis

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