2x+6-5>10+x then combine terms

2x+1>10+x move the 1 to the lfet by subtracting from both sides

2x+1-1> 10+x-1 combine

2x > 9+x subtract x from both sides

2x-x> 9+x-x combine

x>9 solution

Double check

2(9+3)-5>10+9

24-5>19

so x must be greater than 9

I would start by grouping the x terms by putting all the x terms on one side and all the normal numbers on the other.

(add 5 and subtract x to both sides)

2(x+3) -5 +5 -x > 10 + x -x +5 =

2(x+3) – x > 10 +5=

2(x+3) – x > 15

I would then distribute 2 in the 2(x+3) term.

2x+6 – x > 15

Then solve for x again by separating the x terms and the whole numbers. (subtract 6 to both sides)

2x + 6 – x – 6 > 15 – 6=

2x – x > 9

x > 9

^ That should be the answer, but always double check your work!

A term that is more than 9 would be 10, so I would plug in 10 into the first equation.

2(10+3) -5 > 10 + 10

2(13) -5 >20

26 -5 >20

21 > 20

So that is correct. So “x>9” would be the solution.

Re-group: 2x – x > 10 – 6 + 5

Result: x > 9