A few days ago
help on PRECALC problem?
Given sinx = 1/3, find sec x
and an explanation would be nice too thanks
pleaseee help!
Top 2 Answers
A few days ago
Favorite Answer
sec x = 1/cos x, and cos^2x + sin^2x = 1 or cos^2x = 1 – sin^2x
So cos^2 x = 1 – 1/9 = 8/9 and cosx = plus or minus sqrt (8/9) or sqrt 8 / 3. Flip this to get sec x: 3 / sqrt 8, or (3 sqrt8)/ 8
Again, it’s plus or minus unless you know what quadrant you are in (either I or II since sine was positive)
1
A few days ago
sinx = opposite / hypotenuse = 1/3
opposite = 1
hypotenuse = 3
You can find the adjacent side by using the pythagorean theorem.
(adjacent)^2 + (opposite)^2 = (hypotenuse)^2
(adjacent)^2 + 1^2 = 3^2
(adjacent)^2 + 1 = 9
(adjacent)^2 = 8
adjacent = sqrt(8)
secx = 1 / cosx
= 1 / (adjacent/hypotenuse) = hypotenuse / adjacent
= 3 / sqrt(8)
Rationalize and simplify if necessary.
0
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