For example — if you had an equation where Y = 3X+2 — then set X = 0 (so Y = 3*0+2=2) to get a Y intercept of 2.

In your equation, setting X = 0 gives you Y = 0 — and vice versa. So — the X and Y intercepts are both zero.

http://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/beg_alg_tut22_int.htm

Example 2: Graph each linear function by finding the x- and y- intercepts. -3x = y

Step 1: Find the x- and y- intercepts.

Let’s first find the x-intercept.

What value are we going to use for y?

You are correct if you said y = 0.

*Find x-int. by replacing y with 0

*Inverse of mult. by -3 is div. by -3

The x-intercept is (0, 0).

Next, we will find the y- intercept.

What value are we going to plug in for x?

If you said x = 0, you are right.

*Find y-int. by replacing x with 0

The y-intercept is (0, 0)

Hey, look at that, we ended up with the exact same point for both our x- and y-intercepts. As mentioned above, there is only one point that can be both an x- and y- intercept at the same time, the origin (0, 0).

Step 2: Find at least one more point.

Since we really have found only one point this time, we better find two additional solutions so we have a total of three points.

We can plug in any x value we want as long as we get the right corresponding y value and the function exists there.

Let’s put in an easy number x = 1:

*Replace x with 1

So the ordered pair (1, -3) is another solution to our function.

Let’s put in another easy number x = -1:

*Replace x with -1

So the ordered pair (-1, 3) is another solution to our function.

Note that we could have plugged in any value for x: 5, 10, -25, …, but it is best to keep it as simple as possible.

The solutions that we found are:

x y (x, y)

0 0 (0, 0)

1 -3 (1, -3)

-1 3 (1, 3)

y = mx + b

your equation is

y = 3x + 0

Got that?

b is the y-intercept.

Got that?

to get x- intercept, set y = 0

Hope that brings some smile on your face.