find an equation in slope-intercept form for the line that passes through(-3,1)and(-2,3) need answer.?
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y – 1 = 2(x + 3)
y = 2x + 7
or slope = m = (-3 – 1) / (-2 + 3) = -4
y – 1 = -4(x + 3)
y = -4x – 11
Depending on which two points are correct. The first assumes (-3,1) (-2,3). The second assumes (-3,1), (-2,-3)
y = mx + b
and remember … slope is the change in Y over the change in X
y1=1, y2=-3
equation of line is y-y1=(y2-y1/x2-x1)*x-x1
y-1=(-3-1/2+3)*x+3
(y-1)=-4/5*(x+3)
5y-5=-4x-12
5y=-4x-7
y=-4/5*x-7/5
So, i expect that it is the correct answer, which will solve your problem,
Best of Luck!!!!!!!!!!!!!!!!!
m=(y2-y1)/(x2-x1)
m=(-3-1)/(-2-(-3))
m=-4/(-2+3)
m=-4/1
m=-4
y-y1=m(x-x1)
y-1=-4(x-(-3)
y-1=-4x-12
y=-4x-11
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