Find 3 consecutive such that te sum of the largest and 5 times the smallest is -244?

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A few days ago

Anonymous

Favorite Answer

I guess you mean 3 consecutive integers.

Let the smallest one be x. Then the next two are x + 1 and

x + 2.

The largest plus 5 times the smallest is:

x + 2 + 5x

= 6x + 2.

Therefore:

6x + 2 = -244

6x = -246

Dividing by 6:

x = -41.

The integers are therefore -41, -40 and -39.

Check.

The largest is -39.

5 times the smallest is 5*(-41) = -205.

The sum is -244.

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