A few days ago
Factoring problem help?
5(3-4x)^2-8(3-4x)(5x-1)
The correct answer is: (3-4x)(23-60x) but I don’t understand how.
7x(2)(x^2+1)(2x)-(x^2+1)^2(7)
Top 2 Answers
A few days ago
Favorite Answer
notice the (3-4x) is a factor common to both terms so take it out
(3-4x)[5(3-4x)-8(5x-1)] combine like terms in the square brackets
(3-4x)[15-20x-40x+8]
(3-4x)(23-60x)
Same as above : x²+1 is a common factor so take it out
(x²+1)[7x(2)(2x)-(x²+1)7] simplify in the square brackets
(x²+1)[28x²-7x²-7]
(x²+1)(21x²-7) there is a common factor of 7 take out
7(x²+1)(3x²-1) normally factoring stops with rationals but this can be factored over irrationals as
7(x²+1)(√3 x-1)(√3 x+1)
1
A few days ago
Factor 5(3 – 4x)^2 – 8(3 – 4x)(5x – 1)
(3 – 4x)[5(3 – 4x) – 8(5x – 1)]
(3 – 4x)(15 – 20x – 40x + 8)
(3 – 4x)(23 – 60x)
1
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