a bus starting from rest is given a const. acceleration of 5m/s^2 in 10sec…?

a.) what is the final velocity after 10sec.?

b.) what is the displacement after that time?..

need some help guyz..thanx!..

Top 1 Answers

A few days ago

Twiggy

Favorite Answer

a.] using v = u+at, u = 0[starts from rest], a = 5,[given] and t = 10, [given]

v = u + at

v = 0 + 5 x 10

v = 50 m/sec.

b.] use s = ut + 0.5at^2

s = 0 + 0.5 x 5 x 10 x10

s = 2.5 x 100

s = 250 m.

I`m assuming that displacement means distance travelled. Us dumb Brits use a different terminology, and I`ve found it confusing at times……. Twiggy

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