x, x + 1 and x +2, their sum would be 3x +3

Since the first is 2 fifths of the total, we can make the equation:

x = (3x + 3) 2/5, multiply both side by 5

5 x = (3x + 3) x 2

5x = 6x + 6 subtract 6x from both sides

-x = 6; x = -6

Check the answer: -6 x 5/2 = [-6 + -5 + -4] = -15

second number : x + 1 (next integer)

third number : x + 2

sum = x + (x + 1) + (x + 2)

3x +3

first number (x) = 2/5 sum (3x +3)

x=2/5*(3x + 3)

that finds first integer then go back to the beginning to find the last two. Hope this helps 😀

sum=x+(x+1)+(x+2)=3x+3

x=2/5(3x+3)

5x=2(3x+3)

5x=6x+6

-x=6

x=-6

The numbers are -6,-5,-4 (Answer)

check: first one=-6

sum=-15

2/5(sum)=2/5(-15)=-6