-5 – (3)(-2) = -5 + 6 = 1

7/12 + 2/3 – 1/4 = 7/12 + 8/12 – 3/12 = 12/12 = 1

14 5/6 – (-7 2/3) = 89/6 + 23/3 = 89/6 + 46/6 = 135/6 = 45/2

3(-2) – 5(-3) – (-2)^3 = -6 + 15 + 8 = 17

3.5 – 0.05(2) +14.2 / 0.2 = 3.5 – 0.1 + 71 = 74.4

[sqrt(169)-sqrt(64)]/[2sqrt(25)] = (13 – 8) / (2*5) = 5/10 = .5

|5| x |-2| – |-8| = 10 – 8 = 2

B. Evaluate each of the following if x = -3 and y = 2:

3x^2 – 2y^3 = 3(-3)^2 – 2(2)^3 = 27 – 12 = 15

x^3 – xy – 3 = (-3)^3 – (-3)(2) – 3 = 27 + 6 -3 = 30

C. Find:

N if 40% of N is 16

.4N=16

N=16/.4 = 40

D. Solve:

7x – 3 – 2x = 2(x+3)

7x – 3 – 2x = 2x+ 6

5x – 3 = 2x+ 6

3x = 9

x=3

E. Simplify the following:

(4x – 2y)^2

(3/2x + 3)(1/2x – 3)

F. Solve:

2x – 4 < 5x + 8 G. Factor the following completely: 12a^5 - 18a^4 - 6a^3 3(2x - 1) - 4y (2x - 1) H. Solve the system below: 3x - 2y = 7 5x + 2y = 1 I. Simplify and state restrictions: x cannot equal 2, 3, -3 [(5x^2 - 10x)/(x^2 - 5x + 6)] / [(2x^2 + 6x)/(x^2-9)] =[(5x(x - 2))/((x-2)(x-3))] * [(x-3)(x+3)/(2x(x + 3))] =[(5x)/(x-3)] * [(x-3)/(2x)] =(5x)/(2x) = 5/2 J. Solve for x, x || 0, x || -3: (3x-4)/x - (x+1)/(x+3) = 2 [(3x-4)(x+3)]/[x(x+3)] - [(x+1)x]/[x(x+3)] = 2 [(3x-4)(x+3)-(x+1)x]/[x(x+3)] = 2 (3x-4)(x+3)-(x+1)x = 2x(x+3) = 2x^2 + 6x 3x^2+ 5x - 12 -x^2 - x = 2x^2 + 6x 4x - 12 = 6x -12 = 2x x = -6 K. Find: the length and the slope of the line segment connecting A(3, 5) and B(-3, 4) length = sqrt[6^2 + 1] = sqrt(37) Slope = (4-5)/(-3 - 3) = 1/6 L. Graph: 2x + 5y = 10 5y = 10 - 2x y = -2/5x + 10 The graph will look like a line that intersects the y-axis at 10 and goes down two units for every five units that it moves to the right. M. Graph: y = 2x^2 A parabola with the vertex at the origin, branches increasing on both sides as the equation describes. N. Find x, y, z, w: x=70 degrees y = 110 degrees z=40 degrees x=8/sqrt(2) = 4sqrt(2) O. Solve the following equations for x or y: 2^(x+1)=8 x+1 = 3 x = 2 2x^2 - 3x - 5 = 0 0=(2x-5)(x+1) x=-1, x=5/2 x/4 = 3/y = 5/30 x=2/3 y=90/5=18 P. Find: The tenth term of an arithmetic sequence when its first term is 3 and the common difference is 2. 3,5,7,9,11,13,15,17,19,21 21 Q. Find the area of the following figures: x^2 + y^2 = 16 r=4 area=pi*r^2 = 16pi AD = 3cm, BC = 5cm, AE = 2cm 6 is the area of the rectangle BE = 1/2*(BC-AD) = 1 1*2= area of both triangles 2+6=8 R. Graph each of the following: y = -x^2 + 2 Upside-down parabola with vertex at (0,2) y = 2^x http://www.madeasy.de/2/y2x.gif y = sin x http://www.quickmath.com/www02/images/gif/graphs/plot/example4.gif S. Simplify: 2^-3*4^2*16 = 16^2/8 = 32 a^6.9 log 75 - log 3 + log 4 = log 100 = 2 Use the identity sin^2 x + cos^2 x = 1 T. Solve: |x - 3| = 5 x - 3 = 5 x = 8 x-3 = -5 x=-2 2^(2x) - 12(2^x) + 32 = 0 12(2^x) = 32 + 2^(2x) take the log base 2 of the entire equation U. Divide: x^3 + 7x^2 - 11x + 4 by x + 5 __1 + 7 - 11 + 4 -5 |__-5_- 10_105 _ 1_ 2 _ -21 109 x^2 + 2x -21 +109/(x+5)