2) -2/3

3) 3/8

4) 6/7

5) 5/9

(Answer No. 1)

0 . 2 6 6 6

________

1 5√ 4

– 0

¯¯

4 0

– 3 0

¯¯¯¯

1 0 0

– 9 0

¯¯¯¯

1 0 0

– 9 0

¯¯¯¯

1 0 0

– 9 0

¯¯¯¯

1 0

¯¯¯¯

Therefore, the answer is 0.2666… or 0.2667

(Answer No. 2)

Firstly, ignore the negative symbol to solve as normal:

0 . 6 6 6 6

________

3√ 2

– 0

¯¯

2 0

– 1 8

¯¯¯¯

2 0

– 1 8

¯¯¯¯

2 0

– 1 8

¯¯¯¯

2 0

– 1 8

¯¯¯¯

2

¯¯¯¯

Put the negative symbol for the answer.

Therefore, the answer is -0.6666… or -0.6667

(Answer No. 3)

0 . 3 7 5

_______

8 √ 3

– 0

¯¯

3 0

– 2 4

¯¯¯¯

6 0

– 5 6

¯¯¯¯

4 0

– 4 0

¯¯¯¯

0

¯¯¯¯

Therefore, the answer is 0.375

(Answer No. 4)

0 . 8 5 7 1 4

__________

7 √ 6

– 0

¯¯

6 0

– 5 6

¯¯¯¯

4 0

– 3 5

¯¯¯¯

5 0

– 4 9

¯¯¯¯

1 0

– 7

¯¯¯¯

3

¯¯¯¯

Stop the calculation if no repetition decimal value or no final remainder.

Therefore, the answer is 0.85714

(Answer No. 5)

0 . 5 5 5 5

________

9 √ 5

– 0

¯¯

5 0

– 4 5

¯¯¯¯

5 0

– 4 5

¯¯¯¯

5 0

– 4 5

¯¯¯¯

5 0

– 4 5

¯¯¯¯

5

¯¯¯¯

Therefore, the answer is 0.5555… or 0.5556

2)-0.6666(4 significant figures)

3)0.375

4)0.8571(4 significant figures)

5)0.5555(4 significant figures)

It’s simple. Just divide the numerator by the denominator and if the decimal is too long, look at how many significant figures or decimal places the problem requires and state it in a bracket after your answer. Relax, the decimal system is no much different than the fraction system.

such as 4 divided by 15 equals .2666666666

.2/3 would be .6 with a bar on top of it. etc

4 ÷ 15

-2 ÷ 3

3 ÷ 8

etc.

Sometimes you’ll get a really long decimal as your answer. Just round as necessary.

4 divided by 15 = .266

2 divided by 3 = .666

3 divided by 8 = .375

and so on…….

4/15 = 0.27

-2/3 = -0.67

3/8 = 0.38

6/7 = 0.86

5/9 = 0.56

1) .267

2) -.6667

3) .375

4) .85714

5) .5556

.267

-.667

.375

.85714

.556