A few days ago

# let a and be be the roots of of the equation x tothe power of two=mx+2=0. Suppose that a+(1/b) and b+(1/a) are

let a and be be the roots of of the equation x tothe power of two=mx+2=0. Suppose that a+(1/b) and b+(1/a) are the roots of that equation. x to the power of 2=px+q=0. what is q?

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A few days ago

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Did you copy this question down right? It looks very confused, with too many variables to solve.

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4 years ago

The roots of x^2 – mx + 2 = 0 are a and b, as a result, a+b = m …(a million) ab = 2 …(2) [ in case you do no longer know approximately those result, right here is the derivation: for a quadratic equation, with roots x = p and x = q ax^2 + bx + c = a(x-p)(x-q) => ax^2 + bx + c = a( x^2 – (p+q)x + pq ) comparing the coefficients of x^2 and x and constants, p+q = -b/a pq = c/a ] now the roots of x^2 – px + q = 0 are say m=a+(a million/b) and n=b+(a million/a) as a result, mn = q => ( a+(a million/b) )( b+(a million/a) ) = q => ab + (a million/ab) + 2 = q => 2 + (a million/2) + 2 = q (ab = 2, from (2) ) => q = 9/2

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