Help me calculate this function?

Given the function f(x)=5 |x-1|, calculate the following values:

f(x+1)

f(x^2+s

Note: Just to clarify, the x-1 is in between absolute value signs

Top 1 Answers

A few days ago

MsMath

Favorite Answer

f(x) = 5 |x-1|

For f(x+1) replace “x” with “x+1”

f(x+1) = 5 |(x+1) -1| = 5 |x|

For f(x^2 +s) replace “x” with “x^2 +s”

f(x^2 +s) = 5 |(x^2 +s) -1| = 5 |x^2 +s -1|

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