A few days ago
write 2x= 3/8y – 4 in standard form?
help
Top 3 Answers
A few days ago
Favorite Answer
2x= 3/8y – 4 Rearrange
3/8y = 2x -4 = 2(x-2)
8y/3 = 1/[[2(x-2)]
y = 3/8{1\[2{(x-2)]}
y = 3/[16(x-2)]
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A few days ago
I do believe…
2x – 3/8y= -4
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A few days ago
Ax+By=C, ‘C’ is the constant.
‘ can also be written this way:
16x-3y=-32
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