A few days ago
Work Word problem?
Working alone, Ryan can dig a 10ft by 10ft hole in 5 hours Castel can dig the same hole in 6 hours how long would it take if they worked togeather. I need explanation and setup with solution. Thanks
Top 2 Answers
A few days ago
Favorite Answer
Ryan digs 1/5 of the hole in 1hr.
Castel digs 1/6 of the hole in 1hr.
1/5 + 1/6
= (6 + 5) / 30
= 11/30
Together, therefore, they dig 1/5 + 1/6 = 11/30 of the hole in 1hr.
They take 30/11hr. to dig the hole together.
That is 2hr. 8*60/11min.
= 2hr. 480/11min
= 2h4 43 7/11min.
0
A few days ago
First figure out the volume of the hole (Pi*R^2*h)=vol.
volume=3.14×5^2x10ft = 785cubic ft.
If u divide that by the time it takes each to dig it
Ryan=785/5=157 cubic ft/hour
Castel=785/6=130.83 cubic feet/hour
Working together add the two rates 157+130.83=287.83 ft^3/hr is the new rate.
Divide the original volume by that new rate and you get the new time.
785/287.83=2.72 hours
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