A few days ago
Yahoo! King

Trapezoid Geometry Help – Please?

I have a hard time trying to figure out these 2 problems. If any one of you can help, it’d be great. I need all the work/formulas too, not just the answer.

ok here it is:

An ISOSCELES TRAPEZOID has base angles of 45 degrees and bases of lengths, 12 and 32. Find it’s area.

Second one is:

The area of a trapezoid is 144 km squared. The shorter base is 15 km and the height is 6 km. Find the longer base.

man, if anyone of you could really help, it’d more than awesome. thxxx =)

Top 4 Answers
A few days ago
Grandmaster_D

Favorite Answer

1. Use formula A=h(b1+b2)/2

find the height of the trapezoid, using facts given. Both base angles are 45 degrees, so adjacent and opposite sides will be equal. Base 32-base 12= 20. Divide this by 2 and you get 10, which is the length of the adjacent angles. This will also be the height of the trapezoid.

So, 10(12+32)/2 = 440/2 = 220

2. Use same formula, and work backwords

144=6(b1+15)/2

144= 6b1+90/2

144=3b1+45

subtract 45 from each side

99=3b1

33=b1

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A few days ago
Anonymous
Erm, well this is all i know:

The formula to figure out the area of a trapezoid is:

A=h(b1+b2)/2

A=Area

h=Height

b1=base1

b2=base 2

So you would figure out the perpendicular height then times it by b1+b2 then divide the whole answer by 2. I dont know how you will figure out the perpendicular height you may have to draw the shape and measure :S ?

For the second one you use the formula again but in a different way… so

A=H(b1+b2)/2

you times both sides by 2 to get

2A=h(b1+b2)

then divide by H

2A/h=b1 +b2

so times the area by 2 then divide by the height then you will substitue the b1 for 15km and take that away to find b2!

So formula for that will be

(2A/h)-b1=b2

Hope this has helped im not 100% this is right but im in year 9 nd pretty darn good at maths so i hope ive helped!

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4 years ago
massaglia
Make this a triangle question instead of a trapezoid one via reducing the trapezoid into 2 triangles and a rectangle. Even extra useful, we can assume that the triangles are congruent because of the fact the trapezoid is isosceles. The triangle is a proper triangle with angles of 20, 70, and ninety. The element opposite the 20 degree perspective is of length 2, considering the fact that it is 0.5 the adaptation between the two bases (the different 0.5 is for the different triangle). practice the regulation of sines to locate the element we choose, that’s opposite the ninety degree perspective. 2/sin(20) = X/sin(ninety) sin(ninety)=a million, so 2/sin(20) = X, the hypotenuse of the triangle and one element of the trapezoid. Multiply X via 2 to account for the different triangle, upload the bases, and ta-da! you’re completed.
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5 years ago
Anonymous
Wow, thanks! Just what I was looking for. I looked for the answers on other websites but I couldn’t find them.
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