A few days ago
Anonymous

Math question.?

“An L1011 traveled 645 mph with the wind and 575 mph against the wind. Find the speed of the plane in still air and the speed of the wind.”

Do you know the answer? If you do, please also show me how you got to your answer! 🙂

Top 6 Answers
A few days ago
Archie

Favorite Answer

take the plane to be X and the wind to be y

therfor

X+Y=645 and

X-Y=575

therfore if we use simultanius equationswe can work out that 2X=645+575

2X=1220

X=610

if we substitute this into the first equation we get Y =35

therfore X=610 and Y=35

I think!

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A few days ago
brett s
Add the two together then divide it in half

645+575=1220

1220/2= 610

610 is the speed of the plane in still air.

the difference between 610 and 645 = 35 mph is the speed of the wind

(can also do difference of 610 and 575 = 35 mph) you will get a positive and a negative 35 depending on which way you do it, that just means the wind is blowing at you in one direction and away from you on the other.

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A few days ago
dantails
The same speed of the wind? I would just take the average of the two speeds, and divide by two, although that would be assuming the plane was going head-on into the wind, and head-on against it, and that the wind was giving 100% efficient push against the plane, matching the strength of the wind perfectly…

In short, not enough info, but I’d guess 35 MPH, with the plane going 610 in still air.

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A few days ago
God is Good!
Find the difference between the speeds and divide by 2. Add this to the headwind speed and deduct it from the tailwind speed and you get 610 mph in still air. The wind is 35 mph.
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A few days ago
11 year old Slim Shady
im eleven years old and i dont want to do that kind of question when i have my free time outside of school
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A few days ago
someone4me95
use a calculater
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