A few days ago
Anonymous

The sum of 17 consecutive numbers is 306. What is the first number?

The sum of 17 consecutive numbers is 306. What is the first number?

Top 2 Answers
A few days ago
?

Favorite Answer

x + (x+1) + (x+2) +(x+3) +(x+4) +(x+5) +(x+6) +(x+7) +(x+8) +(x+9) +(x+10) +(x+11) +(x+12) +(x+13) +(x+14) +(x+15) +(x+16) = 306

You need to find out what x equals.

17x + 136 = 306

17x = 170

x= 10

Check answer…

10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26 = 306

success!

Hope that explained it a bit. 🙂

3

A few days ago
vaishu_prabha
let us assume that the first number be a

therefore

the sum of the 17 consecutive no is given by

a+(a+1)+(a+2)+……+(a+16)

which is equal to 306(given)

if we combine the variable a we get

17 a’s

if we combine the numbers we get

1+2+3+4+….+16

we can use the formula for the sum of ‘n’ numbers

(n(n+1))/2

here n=16

therefore (16*(16+1))/2

= (16*17)/2

= 136

from the original equation we formed

we get

17a+136=306

now solving for a

17a = 306-136

17a = 170

a=170/17

a=10

therefore the first number is 10

if u want to examine the result

u substitute a=10 in the first equation we formed

it will definitely satisfy.

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