A few days ago
campus_qt101

The perimeter of a lot is 84ft. The length exceeds the width by 16ft. Find the length and the width.?

help PLease..=) Thank you

Top 6 Answers
A few days ago
wiz8

Favorite Answer

Let x = the length and y = the width,so, as length exceeds the width by 16ft: y + 16 = x

As the perimeter of the lot is 84ft: 2x + 2y = 84

Now, we have 2 equations, thus we can find the length and the width with this method:

x = y + 16 – equation 1

2x + 2y = 84 – equation 2

So, by subsitute eq 1 into eq 2, we have:

2(y + 16) + 2y = 84

2y + 32 + 2y = 84

4y = 52

y = 13

Then, subsitute the value of y into eq 1:

x = 13 + 16

x = 29

The answers:

Length = 29ft

Width = 13ft

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A few days ago
jkr17
If the length exceeds the width by 16 ft, then the width is x and the length is x+16. Since the perimeter is 84, you can use the equation 2x+2(x+16)=84. Then you solve the equation as follows:

2x + 2x + 32 =84

4x = 52

x = 13

So, the width is 13 and the length is 29.

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A few days ago
kalemlh
Should be 2x+2x+2(16)=84

4x+32=84

4x=52

x=13

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A few days ago
greta
perimeter of a lot is 84 ft

2(l+b)=perimeter

let length= l

let breath= b

l=b+16(given)

substitute the above to get the ans

2(b+16+b)=84

2(2b+16)=84

2b+16=84/2

2b+16=48

2b=48-16

2b= 32

b=32/2

b=16ft

l=b+16

therefore l=32ft

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A few days ago
mbp
Length is 29 feet

Width is 13 feet.

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A few days ago
Brad B
29 ft x 13ft
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