The perimeter of a lot is 84ft. The length exceeds the width by 16ft. Find the length and the width.?
Favorite Answer
As the perimeter of the lot is 84ft: 2x + 2y = 84
Now, we have 2 equations, thus we can find the length and the width with this method:
x = y + 16 – equation 1
2x + 2y = 84 – equation 2
So, by subsitute eq 1 into eq 2, we have:
2(y + 16) + 2y = 84
2y + 32 + 2y = 84
4y = 52
y = 13
Then, subsitute the value of y into eq 1:
x = 13 + 16
x = 29
The answers:
Length = 29ft
Width = 13ft
2x + 2x + 32 =84
4x = 52
x = 13
So, the width is 13 and the length is 29.
4x+32=84
4x=52
x=13
2(l+b)=perimeter
let length= l
let breath= b
l=b+16(given)
substitute the above to get the ans
2(b+16+b)=84
2(2b+16)=84
2b+16=84/2
2b+16=48
2b=48-16
2b= 32
b=32/2
b=16ft
l=b+16
therefore l=32ft
Width is 13 feet.
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