A few days ago
Anonymous

The length of a rectangle is 5 meters longer than the width?

The length of a rectangle is 5 meters longer than the width. Find the length and width if the perimeter is 54 meters.

Top 5 Answers
A few days ago
Anonymous

Favorite Answer

2 x (length) + 2 x (width) = perimeter

2 ( x) + 2 (x + 5) = 54

2x + 2x + 10 = 54

4x + 10 = 54

4x = 44

x = 44/4

x = 11 (width)

y = 11 + 5 = 16 (length)

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A few days ago
Richard C
I wont do it for you because that way you wont learn. Here is an example.

A rectangle is 3 meters longer than its width. Width is 60m

longside + small side + long side + small side = permimeter

(x+3) + x + (x+3) + x = 60m

so:

4x + 6 = 60

4x = 60 – 6 = 54

x = 54 / 4 = 13.5

X = 13.5 or width

X+3 or 13.5 + 3 = 16.5 or length.

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A few days ago
AnonymousOne
let perimeter = 54

width = w

length = w + 5

then your formula for the perimeter of rectangle is:

P = (2*l) + (2*w) so

54=2(w+5)+2*w

54=2w+10+2w

44=4w

w=11 & w+5=16

so to check: 11+11+16+16=54

hope this helps!

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A few days ago
Beardo
perimeter = 54 = 2l + 2w = 2 (w + 5) + 2w = 4w + 10

4w = 44

w = 11

l = 16

area = l*w = 11*16 = 176 sq m

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A few days ago
The_Yak
w=w

L = w + 5

P = 54

Perimeter = 2L + 2w

2(w + 5) + 2w = 54

2w + 10 + 2w = 54

4w + 10 = 54

4w = 44

w = 11

2(11) + 2L = 54

22 + 2L = 54

L = 16

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