A few days ago

daniel’s sweety

solve the equation. Check for extraneous solutions?

( x^2 + 2………this is squared, i dont know how to make a square root symbol on here)

x^2 + 2 = x + 4

Top 3 Answers

A few days ago

Anonymous

Favorite Answer

if the equation is x to the 2nd power +2 = x + 4

then set the equation equal to zero. x^2 – x – 2. Factoring gives (x-2) (x+1) = 0

set both factors equal to 0 and solve for x.

the answers are x = 2 and x = -1.

To check your solution, plug the answers into the original equation and both sides should equal each other.

If x = 2 then you get 2^2 + 2 = 2 + 4 , so 6 = 6 so it checks.

if x = -1 then you get (-1)^2 + 2 = – 1 +4 , so 3 = 3 so it checks.

therefore, both answers are solutions to the equation.

A few days ago

hayharbr

Is the x^2 + 2 quantity under the square root radical? If so square both sides which makes it x^2 + 2 = (x+4)^2 = x^2 + 8x + 16

2 = 8x + 16

-14 = 8x; x = -14/8

But this doesn’t make much sense so I don’t think I understood yur question.

A few days ago

dpirsq2

First combine like terms.

x^2 – x – 2 = 0

Now factor the trinomial

( x + 1 ) ( x – 2 )= 0

Set each factor equal to 0……..

x + 1 = 0

x = -1

x – 2 = 0

x = 2

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