solve the equation. Check for extraneous solutions?
x^2 + 2 = x + 4
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then set the equation equal to zero. x^2 – x – 2. Factoring gives (x-2) (x+1) = 0
set both factors equal to 0 and solve for x.
the answers are x = 2 and x = -1.
To check your solution, plug the answers into the original equation and both sides should equal each other.
If x = 2 then you get 2^2 + 2 = 2 + 4 , so 6 = 6 so it checks.
if x = -1 then you get (-1)^2 + 2 = – 1 +4 , so 3 = 3 so it checks.
therefore, both answers are solutions to the equation.
2 = 8x + 16
-14 = 8x; x = -14/8
But this doesn’t make much sense so I don’t think I understood yur question.
x^2 – x – 2 = 0
Now factor the trinomial
( x + 1 ) ( x – 2 )= 0
Set each factor equal to 0……..
x + 1 = 0
x = -1
x – 2 = 0
x = 2
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