So, if you have the square root of 1/3x + 2 (plus two is not in the square root). Then what does the 1/3 do wh

So, if you have the square root of 1/3x + 2 (plus two is not in the square root). Then what does the 1/3 do when you graph it? Do you multiply all the y-values by that?

PLEASE HELP.

I will choose a best answer..

Top 2 Answers

A few days ago

captn_carrot

Favorite Answer

Sqrt (1/3X) + 2 = Sqrt(1/3) *(Sqrt X) + 2

(the square of the product is the product of the square.)

Since Sqrt 1/3 = a contstant,

Then the graph will have the square root curve with a slope that is sqrt(1/3) as fast.

Suppose you just had y=1/3X + 2. This is in the form of

y=mx+b.

Then the slope is 1/3 of the slope of m=1.

Similiar for the sqrt(1/3) above.

5 years ago

Anonymous

do your own damn homework…

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So, if you have the square root of 1/3x + 2 (plus two is not in the square root). Then what does the 1/3 do wh

So, if you have the square root of 1/3x + 2 (plus two is not in the square root). Then what does the 1/3 do wh

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