( I don’t want to give you the answer…. that wouldn’t be fair!)

24 tiles cover 144*3 square inches = 432 sq inches

So each tile covers 432/24 = 18 square inches.

Since the tile is square, each side is square root of 18 inches

sqrt(18) = 4.24 (to the nearest hundreth)

2. You have to tile 7.5 feet times 26 feet = 195 sq feet

A box of tile costs $21.50 and covers 3 sq feet.

So, you need 195/3 boxes = 65 boxes

Which cost 65*21.5 = $1397.50

This assumes you can split the tiles perfectly every time. In the real world, that doesn’t happen. If this were real, I’d buy a couple of extra boxes after I figured the minimum number of tile needed.

Also, in the real world, rooms have entrances (whether it’s a hole in the wall or a door doesn’t matter) and people don’t tile those.

3 square feet is the total area and it takes 24 tiles to fill in this area. (In order to visualize this draw yourself an area that equals 3 square feet and then think about 24 tiles covering the area.) This means you need to divide 3/24 to get the area of one of the tiles.

Then there are 12 inches in a foot. So to get down to inches you have to multiply by 12.

3/24*12=1.5

So each tile is 1.5 inches squared

Problem 2:

Basically, there are a couple of steps to this problem.

First you have to figure out the total area you need to cover.

The easiest thing is to imagine the room has 4 walls. The total length of the baseboards along the bottom is 26 and the height is 7.5. Now, you don’t know the base of each individual wall, but if you think of them as 4 square/rectangles lined up in a row with the same height of 7.5, you can easily get your area.

7.5*26=195

So you need enough tiles to cover 195 square feet.

Each box can cover 3 square feet.

195/3=65

Each box costs $21.50, so

65*21.50=1397.50

Means you would need to spend $1,397.50 to cover the walls.