A few days ago
show if the ff. statements are true or false.with complete solutions.thanks.?
sin(squared) 30 degrees + cos(squared)150 degrees + tan(squared)60 degrees= sec 300 degrees
cos 150 deg= 2(cos45 cos 330-sin 135 sin30)
cos 300= cos(squared)30-sin(squared)330
one fifth tan 150= tan 30
Top 2 Answers
A few days ago
Favorite Answer
sin² 30 + cos² 150 + tan² 60
= sin² 30 + cos²(180-30) + tan² 60
= sin² 30 + cos²30 + tan² 60
= 1 + tan² 60 = 1/cos²60 = sec²60
= sec²(360-60) = sec²300
2(cos45cos330 – sin135sin30)
= 2(cos45cos(360-30) – sin(180-45)sin30)
= 2(cos45cos30 – sin45sin30)
= 2cos(45+30) = 2 cos75
cos²30 – sin²330
= cos²30 – sin²(360-30)
= cos²30 – sin²30
= cos60 = cos(360-60)
=cos 300
(1/5)tan 150 ≠ tan 30
0
A few days ago
Sin^2 30 = 0.25, cos^2 150 = 0.75, tan^2 60 = 3 so .25 + .75 + 3 = 4 so if Sec 300 = 4 ::: FALSE
cos 150 = -0.866, 2(cos45 cos330 – sin135 sin330) = 0.517
False
cos 300 = 0.5, cos^2 30 = .75, sin^2 330 = .25
0.5 = 0.75 – 0.25 :: True
4th unsure
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