really need trig help please!?

Almost 3:30am here and i still need to go to school tomorrow, but i keep getting an error when i run through this problem

Find all values of theta in the interval of [0*, 360*] for the equation 16sin^2(theta) + 8sin(theta) +1=0

Top 1 Answers

A few days ago

Anonymous

Favorite Answer

Putting x = sin(theta)

16x^2 + 8x + 1 = 0

(4x + 1)^2 = 0

x = -1/4

In the range [0 ,360) deg

theta = 360 – arcsin(1/4) or 180 + arcsin(1/4)

= 360 – 14.48deg or 180 + 14.48deg

= 345.52deg or 194.48deg

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