A few days ago
yelieu

math problem please help me!?

Two pedestrians left two villages 27 km apart and simultaneously walked towards each other. The first one walked 4km/hr and the second walked 6km/hr. After how many hours did the two pedestrains meet?

ANY help would be very useful to me. I’m taking math and am completely stuck on this problem. I haven’t done math in years, so have no memory what so ever in how to even begin to solve this equation.

THANK YOU SO MUCH!

Top 6 Answers
A few days ago
Mathematician

Favorite Answer

Ok. First, lets draw a diagram.

Pedestrian

A

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Pedestrian

B

Since both, A and B are approaching each other, they are covering the total distance apart from each other.

This distance is given to be 27 kilometers.

Now lets consider the speed at which they are walking. The first (pedestrian A) is walking at 4 km/h. The second one is walking at 6 km/h.

Since and they both started walking at the same time (simultaneously), they decreased the distance “together.”

Think of this as two people trying to finish a task together (in this case it is to cover the distance).

Since they are “working together,” they are covering the distance at a rate of

4 km/h + 6 km/h. which equals 10 km/h.

That is, the rate of A plus the rate of B.

There is a formula that relates Distance, Rate, and Time.

The formula is as follows.

Distance = Rate X Time

(Distance equals Rate multiplied by Time)

The Distance is given to be 27 km. And we found the combined rates of A and B to be 10 km/h.

We can now set up the equation.

Distance = Rate X Time

27 = 10 X Time

This means that Time has to be

27/10 (27 divided by 10)

Which in decimal form is 2.7. (2 point 7) (I was not sure if you were able to see the point between the 2 and the 7).

Since we are trying to find time, the answer is not 2.7, but rather

2.7 hours.

Now, to turn an hour into minutes, all we have to do is multiply by 60. And since

.7 X 60 = 42

This means that the total time is

2 hours and 42 minutes.

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A few days ago
acerflea
2.7 hours.

Since one person walks 4 km/hr and the other walks 6 km/hr and both are walking towards each other, that would mean 1 hour later, the total combined distance they have walked is 10 km (4 + 6). If they can walk 10 km in 1 hour, then they can walk 27 km in 2.7 hours (27 / 10 = 2.7). 2.7 hours is 2 hours and 42 minutes.

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A few days ago
Sephyx
2.7 hours, the 2 people move 10 km/hr combined, take 27 km divided by the distance they move a hour, which is 10, and you get 2.7 hours. Or 2 hours, 42 minutes.
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A few days ago
Anonymous
If the pedestrians move 10 km/h at a combined rate, (4+6), then they would meet in:

27 km divided by (10km/h x 60mins (in an hour)) =

———————————-600 mins.

27 km divided by 600mins = approximately 2 hours and 40 minutes.

Don’t ask me how I got that… lol.

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A few days ago
Anonymous
OK. this is an algebra question.

It will take them the same amount of time to walk so let T=time

So 4T+6T=27

10T=27

T=27/10

2 hours and 42 minutes.

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A few days ago
Anonymous
we did some problems liek this in my math class last year. i’m not sure if this is right but i’ll give it a try:

4km/hr 27km

——— = ———-

6km/hr x

multiply 6 and 27

then divide by 4

[i think this is really wrong..sorry]

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