Quartic function question?
A quartic function passes throught he points (-2, 45), (-1, 48), (0, 45), (1, 48), and (2,45). Determine the equation of the function that passes through these points.
10 points to the first person who can give me the answer.
Favorite Answer
y = ax^4 + bx^3 + cx^2 + dx + e.
Substituting the given values:
a(-2)^4 + b(-2)^3 + c(-2)^2 + d(-2) + e = 45
16a – 8b + 4c – 2d + e = 45 …(1)
a(-1)^4 + b(-1)^3 + c(-1)^2 + d(-1) + e = 48
a – b + c – d + e = 48 …(2)
a0^4 + b0^3 + c0^2 + d(0) + e = 45
e = 45 …(3)
a(1)^4 + b(1)^3 + c(1)^2 + d(1) + e = 48
a + b + c + d + e = 48 …(4)
a2^4 + b2^3 + c2^2 + d2 + e = 45
16a + 8b + 4c + 2d + e = 45 …(5)
From (3):
e = 45
The equations can therefore be reduced to:
16a – 8b + 4c – 2d = 0 …(6)
a – b + c – d = 3 …(7)
a + b + c + d = 3 …(8)
16a + 8b + 4c + 2d = 0 …(9)
Adding (7) & (8):
2a + 2c = 6
a + c = 3 …(10)
Adding (6) & (9):
32a + 8c = 0
4a + c = 0 …(11)
Subtracting (11) from (10):
-3a = 3
a = -1
From (11):
c = 4
Substituting for a & c in (7) & (9):
– b – d = 0
4b + d = 0
Hence b = 0, d = 0
The equation is therefore:
y = -x^4 + 4x^2 + 45.
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