please help me on some math problems? im REALLY CONFUSED?
2, 5, 10, 15, 20
-What is the rate in miles per hour for a messenger who travels 2/3 of a mile in 4 minutes?
-A rectangular field 100 feet long is twice as long as it is wide. The number of feet of fencing needed to enclose the field is:
150, 300, 400, 500, 600
-A restaurant buys fruit in cans containing 3 1/2 cups of fruit each. If the restaurant uses 1/2 cup of the fruit in each serving of its fruit compote, what is the least number of cans needed to prepare 60 servings of the compote?
7, 8, 9, 10, 12
THANK YOU SO MUCH FOR ALL YOUR HELP… IM THE WORST AT WORD PROMBLEMS…
Favorite Answer
2. 60 minutes divided by 4 minutes 15 then 2/3rds of 15 is 10 hmm 10 mph?
3. well if its 1/2 as wide as it is long its 50 feet wide so you think of an actual rectangle ok you know the long sides are 100 feet and there are 2 sides that are long so 200 feet worth for the long way and you know that its 50 feet wide so the shorter sides are 50 a piece 2 of em so thats 100 feet more 100+200 = 300 feet.
4. ok so you can fill 7 1/2 cup servings with 3 1/2 cups 3.5×2=7 ok now you figure out how many times 7 goes into 60 or 60/7 which works out to 8.5 or so which means that to fill 60 servings you will need 9 cans as the number you got was higher than 8.
2. There are 15 4-minute intervals in an hour, so he goes 15*(2/3) miles or 10 miles per hour
3. P= 2 (l+w). If w=l/2, then P=3*l. Then P=300
4. Each can can provide 7 servings. 9*7=63, so answer is 9.
for #2- remember it’s miles per hour. If 2/3 mile is in 4 min., then how many miles would be in 60 min.? You can set up a proportion for then on. If you don’t know how, divide 60/4=15 and then 15×2/3=…
for #3- think of the length of a rectangular as X, then seeing how the width is twice as long, it’ll be 2X. So if the length is 100 feet, the width would be 200 ft. Now since there is 2 width and 2 length, it would be 200+400; the answer being 600.
Hope I helped…
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