Please Help ME!!!Due Tomorrow and I am lost!?
x2 – 7x + 12
x2 – 16
This is a fraction
THis should be x^2-7x+12 as a numerator and x^2-16 as the denominator!
2. Divide:
x2 – 3x + 2÷x2 – 1
7x – 14 7x + 7
These are fractions
This should be x^2-3x+2 as first fractors numerator and 7x-14 for the denominator then divided by the fraction x^2-1 as numerator and 7x+7 as denominator.
3. Simplify:
√[49x12y4z8]
In the brackets should say : 49x^12y^4z^8
The ^ means exponents with the numbers beside it
4. Perform the indicated operations:
3√[3] + 2√[27] –√[12]
5. Multiply:
(8√[6] + 3√[2])(4√[6] – 5√[2])
6. Rationalize the denominator:
5____
√[3] + √[5]
This is also a fraction
Please help me understand the problems and the steps. Thanks
Favorite Answer
= [(x-4)(x-3)] / [(x-4)(x+4)]
= (x-3) / (x+4)
2) [(x^2 – 3x + 2) / (x^2 – 1)] / [(7x – 14) / (7x + 7)]
= [(x^2 – 3x + 2) / (x^2 – 1)] X [(7x + 7) / (7x -14)]
= (x^2 – 3x + 2)(7x + 7) / (x^2 – 1)(7x -14)
= (x – 2)(x – 1)(7x + 7) / (x – 1)(x + 1)(7x -14)
= (x-2)(7x+7) / (x+1)(7x-14)
3) √(49x 2y^4 z^8)
= 7y^2 z^4 √(2x)
4) 3√3 + 2√27 –√12
= 3√3 + 2√(9X3) – √(3X4)
= 3√3 + 6√3 – 2√3
= 7√3
5) (8√6 + 3√2)(4√6 – 5√2)
= 32(√6)(√6) – 40(√6)(√2) + 12 (√6)(√2) – 15 (√2)(√2)
= (32X6) – 28(√6)(√2) – (15X2)
= 192 – 28√12 – 30
= 162 – 28√(4X3)
= 162 – 56√3
6) 5 / (√3 + √5)
= 5 / (√3 + √5) X (√3 – √5) / (√3 – √5)
= 5(√3 – √5) / [(√3)^2 – (√5)^2]
= 5(√3 – √5) / (9 – 25)
= -5(√3 – √5) / 16
= 5(√5 – √3) / 16
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