A few days ago
Please help?
The length of a rectangle is 1 cm longer than its width. If the diagonal
of the rectangle is 4 cm, what are the dimensions (the length and the width) of the
rectangle?
Top 3 Answers
A few days ago
Favorite Answer
(a+b)^2 = c^2 where c is the hypotenuse of the triangle
a=x b= x+1
(x+(x+1))^2=16
(2x)^2 + 1 ^2 =16
4x^2 +1 =16
-1 -1
4x^2 =15
/4 /4
x^2 = 3.75
x = 1.936
1.94 cm and 2.94 cm
or 2 cm and 3 cm
depending on how accurate you need to be
hope this helps
0
A few days ago
the length is x+1 and the width will be x.
since the diagonal is the hypotenuse of a right triangle formed with the length and width, the pythagorian (spelling) theorum can be used, 4^2 = x^2 + (x+1)^2
16 = x^2 + x^2 + 2x + 1 or 2x^2 + 2x +1 = 16
by the quadratic formula x = [1 + (square root) 30]/ 2
and length is that + 1
0
A few days ago
3cm x 2cm
0
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