A few days ago
Physics question?
Suppose a runner runs 100 m in 9.85 seconds. Suppose he reaches his peak velocity in the first 3 seconds 18 meters from the start line. find his peak velocity and acceleration. provide steps
Top 1 Answers
A few days ago
Favorite Answer
You are assuming the runner accelerates from v=0 at a constant rate, and after 3 seconds the velocity is constant.
When the acceleration is constant and the speed changes from v0 to v1 in time t, then:
a = (v1-v0)/t1
d1 (distance, area under graph) = 1/2 (v1-v0) t1 (= 18)
t1 = 3 s
v0 =0 m/s^2
after 3 s you will have constant velocity = v1 and:
d2 = v1 t2
t2 = (9.85-3) s
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