find time

assumption initial velocity=0

force=mass*acceleration

600/80=acceleration=7.5

distance=8

use equation

deltX=initial_velocity*time+

.5*acceleration*time^2

the previous equation simplifies to

8=1/2*acceleration*t^2

solve for t

t=1.46059

First remedy the mass into add-ons parallel and perpendicular to the incline, and convert those to weights. The perpendicular factor occasions the coefficient of static friction equals the friction drive protecting the mass in location. If this drive is lower than the parallel factor of the load, then the mass will slide down the incline. If drive, F, is implemented to the mass perpendicular to the incline, then further friction is created via F*coefficient of friction. When this friction drive further to the friction drive precipitated via the mass same the parallel factor of weight the mass is not going to slide. So, (F + Wperp)* coef fric = Wpar; remedy for F