A few days ago
Anonymous

Need help with an algebra word problem…..?

Solve as many as you can.

1) A train leaves Perryville at 6:00 am and travels east at a rate of 64 mph. As it reaches its destination, Granite City, a westbound train departs from Granite City for Perryville, traveling at a rate of 48 mph. How far is it from Perryville to Granite City by train if the westbound train gets to Perryville at 9:30 am.

2) Write absolute value equations and solve.

Mary lives in a 30-story high rise. Six less than twice her distance above the ground (in stories) is twelve. On what floor does she live?

3) From the model for the 400 m dash, what was predicted for the 2000 Olympics? Compare the prediction with the actual value.

4) Mary Auburn makes three investments. The investment that pays 12% is twice the amount of the account that pays 9%. The amount invested at 10% is $500 more than the amount invested at 9%. If the annual interest income is $1555, how much money is invested at each rate?

Thank you so much.

Top 2 Answers
A few days ago
sdatary

Favorite Answer

For #1, there’s a couple ways to solve it.

Here’s the easiest.. Since the distance is the same, you can take a shortcut and just average the speeds… to get

(56mph) * (3.5 hours) = 2 * (distance in miles).. solve for distance

#2 doesn’t seem to be an absolute value problem… 2x-6 = 12. Where x is the floor she lives on (which is always positive). Solve for x. I suppose you could put absolute values around the x… but that seems a little silly. Maybe there’s something I’m missing.

For #3, I’m assuming that the “model” is something that was referenced earlier in the textbook – which we wouldn’t know anything about (are you even reading these questions?)

For #4, make x equal the amount invested at 9%… y equal the amount invested at 12%… and z equal the amount invested at 10%. You can express this word problem as three equations.

y = 2x

z = x + 500

x + y + z = 1555

The goal is to reduce everything down to one variable.

Solve the first equation for x to get…. x = y/2

Now plug in y/2 into the second equation where the ‘x’ to get… z = y/2 + 500.

Now plug everything into the third equation… y/2 + y + y/2 + 500 = 1555… solve for y

Now that you’ve figured out y, you can plug that value into the other two equations to find x and z

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A few days ago
Jeff S
The first 2 appear to be straight forward.

1) Distance=3 1/2 x 48 =168 miles

2) 2x – 6 =12 so x=9. She lives on the 9th floor.

Can’t do 3 without the diagram and it’s too late to bother with 4 – sorry.

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