A few days ago
Beautiful Disaster

Need help with a huge math assignment!!!?

My teacher assigned us four numbers that we have to have a consecutive set of numbers to. My #s are 5,5,6,7 and I have to get 1-20. I can add, subtract, multiply, divide, use exponets, and square roots.

I cant use the 4 numbers twice in 1 problem, but I can have a double digit.

Please help!!! I have been working on this for the past two days, and I can only come up with 3, 9, 11, 12, and 13.

Please help!!!!

Top 3 Answers
A few days ago
Capn

Favorite Answer

RULES:

Use 5,5,6,7

Using all four numbers each time.

Ex: (5+7)-(5+6)=1

I’ll be back with an answer in a few minutes. Here are the ones so far:

1 5+7-5-6

2 (7-5)*(6-5)

3 (5*5-7)/6

4 (7*5)-(5^2)-6

5 7*5-6*5

6 (6^2) – (7*5)+5

7

8 65-57

9

10 75-65

11

12 6+7-5/5

13 5/5*6+7

14 6+7+5/5

15

16

17 7*6-5*5

18 (5+5-7)*6

19

20

7 7+(5-5)*6

9 ((5*5-7)/6)^2 [the answer for 3 squared]

16 ((7*5)-(5^2)-6)^2 [the answer for 4 squared]

15 75-5*6

20 65/5+7 (Elk_of_hope’s answer)

11 you said you have.

I’m giving up on the 19 — No I’m not…

19 75-56

Thanks for the distraction from work… Now it’s time to go home.

1

A few days ago
Anonymous
Haha crazy… well maybe I can offer a few 😀

1 = 5 / 5 + 7 – 6

5 = 5^7 / 5^6

17 = (7 * 6) – (5 * 5)

18 = 5 * 6 – 5 – 7

That’s all I can think of right now… good luck!

0

A few days ago
Esox
here are some i can think of:

5-5+7-6=1

5/5+7-6=2

75-65=10

65-57=8

5*6-5-7=18

6*(7-5)+5=17

6+7+5/5=14

(5*7-5)/6=5

SQRT(76+SQRT(5*5))=9

and if you SQRT(9) [ SQRT(76+SQRT(5*5)) ] you can get 3

65/5+7=20

0