x=c/(a+b) divide both sides by a+b

restrictions…a cannot equal the opposite of b, b cannot equal the opposite of a ( if they did the numerator would equal zero…division by zero is undefined

x(b-c)=-c factor out x

x=-c/(b-c) divide both sides by b-c

restrictions b cannot equal c…if b=c the denominator would equal zero…division by zero is undefined…

This will give you x(a+b) = c. Next, divide both sides by (a+b). They cancel out on the left side, giving you x = c / (a+b).

The only restriction is, a+b cannot equal zero.

Next, bx – cx = -c. Again, use the distributive property and get : x(b-c) = -c. Divide by b-c on both sides to get:

x = -c / (b-c). The restriction from before remains, except that it is now b-c that cannot equal zero. Hope that helps!