A few days ago
natalie

Math- Problem Solving?

I can’t figure this one out for the life of me!! If you can help me out, it will be much apreciated!

The town of Mittville is organizing a softball league. The athletic office has asked you to help figure out a schedule. There are 10 different teams in the league. If each team is to play every other team only once, how many games will have to be schedules? Why?

Top 4 Answers
A few days ago
John V

Favorite Answer

Each team plays 9 games, so ‘unique’ games are 9+8+7…+1 = 9*10/2 = 45. By unique we need to distinguish between for example team 1 playing team 4, and team 4 playing team 1. We need to count this only once.
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A few days ago
Troy G
There will be 45 games.

Start with team 1, they will play 9 other teams, so there are 9 games.

Team 2 will play 9 teams as well, but you already counted team 1, so that is another 8 unique games.

Team 3 will play 9 teams too, but you already counted teams 1 and 2, so that is another 7 unique games.

Continue this process and you will have 9+8+7+6+5+4+3+2+1=45.

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A few days ago
chasm81
You’ve got 10 teams. Each of those 10 teams will have to play 9 games in order to play every team in the league once (they can’t play themselves). So, 10 teams playing 9 games = 90 games total.
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A few days ago
theshort1
this is a tree type thing. So 2 teams play at each time. lets name all of the teams as letters a-j

team A will play:

B C D E F G H I J

team B will play the same teams minus A because they already played them:

C D E F G H I J

team C will play all minus A and B

D E F G H I J

team D will play all minus A B and C

E F G H I J

team E will play all minus A B C and D

F G H I J

team F will play all minus A-E

G H I J

team G will play all minus A-F

H I J

team H will play all minus A-G

I J

team I will play all minus A-H

J

now count all of those letters underneath the “team _ will play all minus _-_” I think thats 45, but you can count for yourself.

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