Math Problem Please Help,,,,,?

A number of counters can be grouped exactly into 5’s, 6’s and 9’s.

Find the smallest possible number of counters.

Top 2 Answers

A few days ago

Maverick

Favorite Answer

Here’s how to get the answer in case you have another problem like it.

find the prime factors for all 3 numbers (not including 1)

5 = 5

6 = 2,3

9 = 3,3

now you pick the most for each factor

5 from 5

2 from 6

3,3 from 9

so answer is 5 * 2 * 3 * 3 = 90

this is also called the Least common Multiple, or Least Common Denominator

Hope this helps

A few days ago

gradstudent309

Revised Answer:

90.

90/5 = 18

90/6 = 15

90/9 = 10

math question.. really easy.. its like for 9th grade?

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