A few days ago
Math Problem Please Help,,,,,?
A number of counters can be grouped exactly into 5’s, 6’s and 9’s.
Find the smallest possible number of counters.
Top 2 Answers
A few days ago
Favorite Answer
Here’s how to get the answer in case you have another problem like it.
find the prime factors for all 3 numbers (not including 1)
5 = 5
6 = 2,3
9 = 3,3
now you pick the most for each factor
5 from 5
2 from 6
3,3 from 9
so answer is 5 * 2 * 3 * 3 = 90
this is also called the Least common Multiple, or Least Common Denominator
Hope this helps
0
A few days ago
Revised Answer:
90.
90/5 = 18
90/6 = 15
90/9 = 10
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