math i need help so i can help my son?
1. There is a coordinate grid with a line that contains the points (3,-3) and (3,4) describe the slop.
A)positive slope
B)negative slope
C)slope of zero
D)undefined slope
2.There is a coordinate grid with a line that contains the points (1,-3) and (-2,3) Describe the slope of the line
A)positive slope
B)negative slope
C)slope of zero
D)undefined slope
3. There is a coordinate grid containing triangle A B C. The coordinate of point A are (-4,-2). The coordinates of B are (-2,2). The coordinates of point C are (4,-1).Is this triangle a right triangle? Be sure that you show work and explain your answer.
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(3,-3) and (3,4)
going from -3 to 4 is a seven point change, but going from 3 to 3 is a zero change. 7/0 is undefined.
2. (1,-3) and (-2,3)
the change in the y-values is from -3 to 3 which equals 6.
the change in the x-values from 1 to -2 which equals a -3.
6/-3 = -2 a negative slope.
If you prefer the formula method:
given (x1,y1) and (x2,y2), the
slope equals (y2-y1)/(x2-x1)
VERY important to keep make the substration in the same direction each time.
3. For a right triangle, one angle needs to exactly 90 degrees. When lines intersect with with slopes that are the negative inverse of each other, they are perpendicular (90degrees).
Let’s find the slopes of the three lines:
LineAB = (-4,-2) and (-2,2), slope = (2- -2)/(-2 – -4) = 4/2 = 2
LineBC = (-2,2) and (4,-1), slope = (-1-2)/(4- -2) = -3/6 = -1/2
LineAC = (-4,-2) and (4,-1), slope = (-1- -2)/(4- -4) = 1/8
Since 2 and -1/2 are negative inverses of each other, those lines intersect at 90 degrees; thus, forming a right triangle.
2) b- negative slope (think of it this way, from either point given, to access the next point on the line following the grid, one has to go first in a positive direction, then in a negative direction.. a negative times a positive still gives you a negative)
3) Yes, this is a right triangle. The easiest way to do this problem is to think logically. In order for a right triangle to exist here, the lines AB and BC must be perpendicular to each other (to form a 90 degree angle). So you must find the slope for each line. The formula for slope is (y2-y1)/(x2-x1).
Therefore, for line AB, the formula looks like:
m=slope
m= (2 – -2)/(-2 – – 4) then you need to cancel out the negatives
m= (2+2)/(-2+4)
m= 4/2
m= 2
For line BC, the formula looks like:
m= (-1 – 2)/ (4 – – 2)
m= -3/ (4+2)
m= -3/6
m= -1/2
In order for lines to be perpendicular to each other, their slopes must be the negative reciprocal of each other. Therefore the negative reciprocal to a slope of 2 (as seen in line AB) is -1/2 (as seen in line BC).
If you have any further questions, you can check this website for an easy explanation. http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut15_slope.htm
Hope this helps!
2. B because looking from left to right the line goes downhill…so it’s negative.
3. it IS a right triangle, but you have to graph it out to know how, i just drew it out and the top angle is 90 degrees, but it probably has something to do with the slopes of the sides….
2. The slope of the line is negative because from it falls from the left side
Sorry the third one i have to work out on paper (if i had a paper right now i would…) sorry but I hope i helped
If you draw out a grid and plot these points, you will see that the line connecting the two point goes from down to up, representing a positive slope.
2.) Negative slope.
Again, if you draw this out, you will see the opposite affect, representing a negative slope.
3.) Yes, this is a right triangle, if you draw it out, you will see the right angle at one of the corners of the triangle.
2. b – the slope goes down from left to right
3. No.It would be a right triange if coordinate A was (2,-1)
2) B, negative slope
3)
vector AB(vector from A to B) = (2,4)
vector CB(vector from C to B) = (-6,3)
dot product of these = zero
(2*(-6)) + (4*3) = 0
so the lines AB and CB are perpendicular
hence there is a right angle at point B
2. B Slope goes down (like this…\)
3. I can not help…sorry.
try the Internet(google)
type in the questions and the answers will come up!
hope this helps you
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